1. On sports day, if thirty children were made to stand in a column, 16 columns could be formed. If 24 children were made to stand in a column, how many columns could be formed?
A. 25
B. 39
C. 20
D. 45
Answer- C
2. When 56 subtract from a number, it reduces to 86%, what is the 30% of that number?
A. 160
B. 150
C. 130
D. 120
Answer - D
3. If one-fifth of two sixth of a number 16, what is the number?
A. 360
B. 240
C. 120
D. 60
Answer - B
4. If the diagonal of a square is 6 inches, then the area of the square would be ( in sq. Inches)?
A. 9
B. 12
C. 18
D. 36
Answer - C
5. If cost prices of 15 articles is equal to the selling prices of 10 articles, what is the gain percentage?
A. 40%
B. 50%
C. 25%
D. 30%
Answer - B
6. A merchant sold two chairs for Rs. 100 each. On one chair he gains 10% and on the other chair he losses 10%. Find his gain or loss in rupee?
A. Gain of rupees 5
B. Gain of rupees 2.02
C. Loss of rupees 2.02
D. No loss or no gain
Answer - C
7. If a man buyes an article 20% less than its marked price and sells at 20% more than the marked price, then calculate his gain percentage?
A. 20%
B. 40%
C. 50%
D. 100%
A. 25
B. 39
C. 20
D. 45
Answer- C
2. When 56 subtract from a number, it reduces to 86%, what is the 30% of that number?
A. 160
B. 150
C. 130
D. 120
Answer - D
3. If one-fifth of two sixth of a number 16, what is the number?
A. 360
B. 240
C. 120
D. 60
Answer - B
4. If the diagonal of a square is 6 inches, then the area of the square would be ( in sq. Inches)?
A. 9
B. 12
C. 18
D. 36
Answer - C
5. If cost prices of 15 articles is equal to the selling prices of 10 articles, what is the gain percentage?
A. 40%
B. 50%
C. 25%
D. 30%
Answer - B
6. A merchant sold two chairs for Rs. 100 each. On one chair he gains 10% and on the other chair he losses 10%. Find his gain or loss in rupee?
A. Gain of rupees 5
B. Gain of rupees 2.02
C. Loss of rupees 2.02
D. No loss or no gain
Answer - C
7. If a man buyes an article 20% less than its marked price and sells at 20% more than the marked price, then calculate his gain percentage?
A. 20%
B. 40%
C. 50%
D. 100%
Answer - C
8. A cube of lead with edges measuring 6 cm. each is melted and formed in 27 equal cubes. What will be the length of the edges of the new cubes?
A. 1.5 cm
B. 0.5 cm.
C. 2 cm.
D. 1 cm.
Answer - C
Solve- volume of the cube 6 *6*6= 216 cubic cm.
Let length of one side of each cubes are M cm volume of the each cube M^3.
So, 27M^3=216
M= 2 cm
9. If 4Y- 24<8. Which of the following would not be the correct value of Y?
A. 7
B. 8
C. 9
D. 12
Answer - A
10. A can do a piece of work in 20 days, B in 15 days and C in 12 days. In how make days can A finish the work if he is assisted by B on one day and C on the next day alternately?
A. 14
B. 10
C. 9
D. 8
Answer - D
Solve- In 2 days A, B and C work together 1/20×2+1/15+1/12=1/10+1/15+1/12=1/4. So work will be finished by 8 days.
11. If the difference between three times and seven times of a number comes to 36, what is that number?
A. 12
B. 18
C. 6
D. 9
Answer - D
Solve - Let the is X, so three times of the number is 3X. And seven times of the number 7X. Difference is 7X- 3X=4X
According to the question 4X= 36 or X=9
12. A shopman bought apples at the rate of 7 for rupee and sold them at a profit of 40%. How many apples he sells for a rupee?
Answer - A
Solve - Let shopman bought 7 apples at 1 rupee. So, cost price of one apple is 1/7 rupee. He made profit 40%. So C.P. is 100 rupee then S.P. is 140 rupee. 140/100×1/7=1/5 rupee one apple. So he sells 5 apples at one rupee.
13. A team losses 8 matches, wins 3 and draws 4. What is the percentage of matches won?
A. 30%
B. 20%
C. 27%
D. 25%
Answer - B
Solve - total matches played 15 and won 3 matches. So, 3/15×100=20%
14. If 664 be divided into three parts such that 4 times the first may be equal to 5 times the second and 7 times the third. What is the first part?
A. 280
B. 270
C. 340
D. 250
Answer - A
Solve - 4 times of first part = 5 times of second part = 7 times of third part. So, ratio are 1/4:1/5:1/7 = 35:28:20, 664/83×35=280
15. A bag contains 25 paisa, 10 paisa and 5 paisa coins in the ratio 1:2:3. If their total value is Rs. 30 what is the number of 5 paisa coins?
A. 50
B. 150
C. 125
D. 175
Answer - B
Solve - let paisa turn into rupee. 25 paisa = 1/4 rupees , 10 paisa = 1/10 rupees, 5 paisa = 1/20 rupees.
So, total value are 1/4×x+1/10×2x+1/20×3x
= x/4+x/5+3x/20
= 12x/20
According to the question
12x/20 = 30
X = 150
16. The average salary per head of all the workers in a factory is Rs. 95. The average salary of 15 officers are Rs. 525 and the average salary per head of the rest Rs. 85. Find the total number of workers in the factory?
A. 550
B. 660
C. 700
D. 800
Answer - B
Let total workers in the factory be X.
According to the question
95X=15×525+(X-15)×85
or 10X=15(525-85)
or 2X=3×440
or X=660
17. How many bricks 20 cm. by 10 cm. will be be needed to have the floor of a room 25 m long and 16 m wide?
A. 15000
B. 17000
C. 19000
D. 20000
Answer - D
18. A sum of Rs. 6.25 is made up of 80 coins which are either 10 paisa or five coins. How many there are of each kind?
A. 38:41
B. 45:36
C. 39:41
D. 37:43
Answer - B
18. The length, breath and thickness of a rectangular coil are as 7:4:3 and its whole surface is 1098 sq.cm. Find the thickness.
A. 12cm.
B. 14cm.
C. 9cm.
D. 15cm.
Answer - C
According to ratio length, breadth and hight are 7a, 4a and 3a. So 2(7a×4a+4a×3a+3a×7a)=1098
or, a=3
So hight will be 3a=3×3=9cm.
19. Of 1000 inhabitants of a town 60% are male of whom 20% are literate. If all the inhabitants 25% are literate. What percent of the females of the town are literate?
A. 22.5
B. 27.5
C. 30
D. 32.5
Answer - D
Of 1000 inhabitants 60% are male, so total male are 600, of whom 20 % are literate.
Total literate male are 600×20/100=120 male. Total literate inhabitants are 25% or 250 inhabitants, so female literate are 250-120=130.
Total females are 400. Percentage of literate females are 130/400×100 =32.5%
20. A and B enter into a partnership investing Rs. 12000 and Rs. 16000 respectively. After 8 months C also joins the the business with a capital of Rs. 15000. The share of C in a profit of 45600 after 2 years will be.
A. Rs. 15000
B. Rs. 14500
C. Rs. 12000
D. Rs. 20000
Answer - C
A:B:C= 12000×24:16000×24:15000×16=12:16:10=6:8:5
So C will get share of profit
5/19×45600=12000 Rs.
21. Find the length of the bridge which a train 130 m long traveling at 45 km an hour can cross in 30 seconds.
A. 125m
B. 120m
C. 230m
D. 245m
Answer - D
In 30 seconds train cross 45000/3600×30=375m
So, length of the bridge 375-130=245m
22. A circular wire, whose radius is 42cm. Converts to a rectangular form. If the ratio of its length and breadth is 6:5, then what is the measurement of its smaller side?
A. 60cm
B. 30cm
C. 75cm
D. 132cm
Answer - A
Perimeter of the circular wire
2×22/7×42=264cm
Perimeter of the rectangular form 2(6x+5x)cm
So, 2(6x+5x)=264
Or, 11x=132
Or, x=12
So, smaller side is 5×12=60cm
23. The volume of two cylinders are equal. If the ratio of their radius is 2:3, then what is the ratio of their heights?
A. 9:3
B. 2:3
C. 3:2
D. 9:4
Answer - D
24. If the radius of the circle is reduced to half of its original size, then what is the ratio of circumference and radius of the new circle?
A. 2×22/7
B. 1
C. 22/7
D. 22/7r
Answer - C
25. A train reaches from K statito to L station in 45 minutes at the speed of 60km/hr. If at the time of coming back his speed is decreased by 6km/hr., then how more time train will take to reach K?
A. 25 min
B. 50 min
C. 15 min
D. 30 min
Answer - B
At time of coming back train speed is 60-6=54km/hr.
Or 15 mitre /second.
Time taken at return (60×5/18×45)÷15=750÷15=50 minutes.
26. A man passes through the diagonal of a square ground in 3 seconds at the speed of 6km/hr. What is the area of the ground?
A. 1.62 sq.mt.
B. 13.6 sq.mt
C. 12.5 sq.mt
D. 15.36 sq.mt
Answer - A
At speed of 6km/hr, the man passes in 3 seconds 3600/6000×3=1.8 mt.
Square of the diagonal x root over 2
So, x root over 2=1.8
or, x=1.8/root over 2
or, x to the power 2=3.24/2
or, x= 1.62 sq.mt.
27. The ratio between the perimeter and the breadth of a rectangle is 5:1. If the area of the rectangle 216 sq.cm, then what is the length of the rectangle?
A. 24cm
B. 18cm
C. 16cm
D. 12cm
Answer - B
Solve - 2(L+B):B=5:1
Or, 2L+2B:B=5:1
Or, 2L+2B/B=5/1
Or, 2L+2B=5B
Or, 2L=5B-2B
Or, 2L=3B
Or, L:B=3:2
Let L is 3x and B is 2x
According to question
3x ×2x=216
Or, x=6
So, length of the rectangle is 3×6=18cm.
28. The difference between the digits of a two digits number is one-twelfth of the number. What is definitely the sum of the digits of that number?
A. 8
B. 10
C. 6
D. Data inadequate
Answer - D
29. 75% of a number, when added to 75 is equal to the number. What is the number?
A. 380
B. 300
C. 226
D. 215
Answer - B
Solve - according to the question
0.75x + 75=x
Or, x - 0.75x=75
Or, 0.25x=75
Or, x =300
30. If 70% of the students in a school are boys and the number of girls be 504, then what is the number of boys?
A. 3158
B. 2167
C. 1176
D. 1080
Answer - C
Solve - Total students in the school
30%=504
Or, 100%=504/30×100
Or, 100%=1680
So, boys are 1680 - 504=1176
31. What is the smallest number by which 3600 be divided to make it perfect cube?
A. 300
B. 180
C. 450
D. 560
Answer - C
32. The ratio of a man's and a women's work is 5:3. If 3 men and 5 women take 17 days to do a piece of work, how many days will 5 men and 3 women take?
Answer - B
Solve - ratio of work power of a man and woman is 5:3
So, work power of 3 men = work power of 5 women.
5 men = 5×5/3 women
25/3 women + 3 women =34/3 women.
So, 10 women work in 17 days
Or, 1 woman work in 17×10
Or, 34/3 women work in 170×3/34=15 days.
33. If A gets 25% more than B and B gets 20% more than C. The share of C out of the sum of Rupees 740 is?
A. Rs. 300
B. Rs. 200
C. Rs. 240
D. Rs. 350
Answer - B
Let C gets 100 Rs. So B gets 120 Rs. A gets 25% more than B, so A gets 120 - 120 of 25%=120+30=150 Rs. Together they get 100+120+150=370 Rs. So, C gets 200 Rs.
34. The side of a square is doubled. How many time will the area increase?
A. 9
B. 4
C. 2
D. 3
Answer- D
Solve - side of a square 10 units. So area is 10×10=100 sq.unit. If side is doubled 10×2=20 units. Area will be 20×20=400 sq.unit.
400-100=300 sq.unit.
Area increase 3 times.
35. Which of the following fraction is the largest?
4/5, 7/9, 11/13, 17/19
A. 17/19
B. 11/13
C. 7/9
D. 4/5
Answer - A
36. The population of city increases at the rate of 4% p.a. But there is an additional annual increase of 1% in the population due to influx of job seeders. The percentage increase in the population after 2 years is__.
A. 10
B. 10.25
C. 10.75
D. 11
Answer - B
Solve - first year population increase 4%+1%=5%
Second year increased (100+5)×5%=5.25%
After 2 it will be (5+5.25)%=10.25%
37. After spending 1/2 of his salary for household expenses, 1/4th for rent and 1/5th for travel expenses, man deposits the rest in the bank. If his monthly deposits in the bank account to Rs. 50. What is his monthly salary?
A. 800
B. 900
C. 500
D. 1000
Answer - D
Let his salary is 100Rs. Household expenses 1/2 of his salary or 100×1/2=50Rs.
For rent he expenses 1/4 or 100×1/4=25Rs. Travel expenses 100×1/5=20Rs.
Total expenses 50+25+20=95Rs.
Deposits in the bank is 100-95=5Rs.
According to the question
5Rs=50Rs
Or, 1Rs. =50/5 Rs.
Or, 100Rs.=50/5×100=1000Rs.
38. By how much percent must 68 be increased to change it to 85?
A. 20%
B. 100/3%
C. 25%
D. 50/3%
Answer - C
85-68=17
17×100/69=25%
39. Six students obtained 57, 53, 51, 41 and 23 marks in an examination. The teacher however, gave the last three students additional marks just enough to ensure that they had the minimum of 50 marks. In the process, the average score of the students improve by (approx).
A. 6
B. 5
C. 4
D. 4.5
Answer - B
Solve - First 3 students get number above 50. Last 3 students get number below of 50. For 50 number teacher gives 50-47=3 , 50-41=9 and 50-33=17. Total number give 3+9+17=29. So, average number given by the teacher 29/6=5(about).
40. If A, B and C earn Rs. 150 per day while A and C earn Rs. 94 per day and B and C earn Rs. 76 per day. Then C's earnings per day is----
A. Rs. 40
B. Rs. 20
C. Rs. 90
D. Rs. 36
Answer - B
Solve - B earns per day 150-94=56 Rs.
C earns per day 76-56=20 Rs.
40. A cube of lead with edges measuring 6 cm. each is melted and formed in 27 equal cubes. What will be the length of the edges of the new cubes?
A. 1.5cm
B. 0.5cm
C. 2cm
D. 1cm
Answer - C
Solve - volume of the cube is 6×6×6=216 cubic cm.
Let new each side of small cubes are X.
So, 27X^3=216
Or, X=2
8. A cube of lead with edges measuring 6 cm. each is melted and formed in 27 equal cubes. What will be the length of the edges of the new cubes?
A. 1.5 cm
B. 0.5 cm.
C. 2 cm.
D. 1 cm.
Answer - C
Solve- volume of the cube 6 *6*6= 216 cubic cm.
Let length of one side of each cubes are M cm volume of the each cube M^3.
So, 27M^3=216
M= 2 cm
9. If 4Y- 24<8. Which of the following would not be the correct value of Y?
A. 7
B. 8
C. 9
D. 12
Answer - A
10. A can do a piece of work in 20 days, B in 15 days and C in 12 days. In how make days can A finish the work if he is assisted by B on one day and C on the next day alternately?
A. 14
B. 10
C. 9
D. 8
Answer - D
Solve- In 2 days A, B and C work together 1/20×2+1/15+1/12=1/10+1/15+1/12=1/4. So work will be finished by 8 days.
11. If the difference between three times and seven times of a number comes to 36, what is that number?
A. 12
B. 18
C. 6
D. 9
Answer - D
Solve - Let the is X, so three times of the number is 3X. And seven times of the number 7X. Difference is 7X- 3X=4X
According to the question 4X= 36 or X=9
12. A shopman bought apples at the rate of 7 for rupee and sold them at a profit of 40%. How many apples he sells for a rupee?
Answer - A
Solve - Let shopman bought 7 apples at 1 rupee. So, cost price of one apple is 1/7 rupee. He made profit 40%. So C.P. is 100 rupee then S.P. is 140 rupee. 140/100×1/7=1/5 rupee one apple. So he sells 5 apples at one rupee.
13. A team losses 8 matches, wins 3 and draws 4. What is the percentage of matches won?
A. 30%
B. 20%
C. 27%
D. 25%
Answer - B
Solve - total matches played 15 and won 3 matches. So, 3/15×100=20%
14. If 664 be divided into three parts such that 4 times the first may be equal to 5 times the second and 7 times the third. What is the first part?
A. 280
B. 270
C. 340
D. 250
Answer - A
Solve - 4 times of first part = 5 times of second part = 7 times of third part. So, ratio are 1/4:1/5:1/7 = 35:28:20, 664/83×35=280
15. A bag contains 25 paisa, 10 paisa and 5 paisa coins in the ratio 1:2:3. If their total value is Rs. 30 what is the number of 5 paisa coins?
A. 50
B. 150
C. 125
D. 175
Answer - B
Solve - let paisa turn into rupee. 25 paisa = 1/4 rupees , 10 paisa = 1/10 rupees, 5 paisa = 1/20 rupees.
So, total value are 1/4×x+1/10×2x+1/20×3x
= x/4+x/5+3x/20
= 12x/20
According to the question
12x/20 = 30
X = 150
16. The average salary per head of all the workers in a factory is Rs. 95. The average salary of 15 officers are Rs. 525 and the average salary per head of the rest Rs. 85. Find the total number of workers in the factory?
A. 550
B. 660
C. 700
D. 800
Answer - B
Let total workers in the factory be X.
According to the question
95X=15×525+(X-15)×85
or 10X=15(525-85)
or 2X=3×440
or X=660
17. How many bricks 20 cm. by 10 cm. will be be needed to have the floor of a room 25 m long and 16 m wide?
A. 15000
B. 17000
C. 19000
D. 20000
Answer - D
18. A sum of Rs. 6.25 is made up of 80 coins which are either 10 paisa or five coins. How many there are of each kind?
A. 38:41
B. 45:36
C. 39:41
D. 37:43
Answer - B
18. The length, breath and thickness of a rectangular coil are as 7:4:3 and its whole surface is 1098 sq.cm. Find the thickness.
A. 12cm.
B. 14cm.
C. 9cm.
D. 15cm.
Answer - C
According to ratio length, breadth and hight are 7a, 4a and 3a. So 2(7a×4a+4a×3a+3a×7a)=1098
or, a=3
So hight will be 3a=3×3=9cm.
19. Of 1000 inhabitants of a town 60% are male of whom 20% are literate. If all the inhabitants 25% are literate. What percent of the females of the town are literate?
A. 22.5
B. 27.5
C. 30
D. 32.5
Answer - D
Of 1000 inhabitants 60% are male, so total male are 600, of whom 20 % are literate.
Total literate male are 600×20/100=120 male. Total literate inhabitants are 25% or 250 inhabitants, so female literate are 250-120=130.
Total females are 400. Percentage of literate females are 130/400×100 =32.5%
20. A and B enter into a partnership investing Rs. 12000 and Rs. 16000 respectively. After 8 months C also joins the the business with a capital of Rs. 15000. The share of C in a profit of 45600 after 2 years will be.
A. Rs. 15000
B. Rs. 14500
C. Rs. 12000
D. Rs. 20000
Answer - C
A:B:C= 12000×24:16000×24:15000×16=12:16:10=6:8:5
So C will get share of profit
5/19×45600=12000 Rs.
21. Find the length of the bridge which a train 130 m long traveling at 45 km an hour can cross in 30 seconds.
A. 125m
B. 120m
C. 230m
D. 245m
Answer - D
In 30 seconds train cross 45000/3600×30=375m
So, length of the bridge 375-130=245m
22. A circular wire, whose radius is 42cm. Converts to a rectangular form. If the ratio of its length and breadth is 6:5, then what is the measurement of its smaller side?
A. 60cm
B. 30cm
C. 75cm
D. 132cm
Answer - A
Perimeter of the circular wire
2×22/7×42=264cm
Perimeter of the rectangular form 2(6x+5x)cm
So, 2(6x+5x)=264
Or, 11x=132
Or, x=12
So, smaller side is 5×12=60cm
23. The volume of two cylinders are equal. If the ratio of their radius is 2:3, then what is the ratio of their heights?
A. 9:3
B. 2:3
C. 3:2
D. 9:4
Answer - D
24. If the radius of the circle is reduced to half of its original size, then what is the ratio of circumference and radius of the new circle?
A. 2×22/7
B. 1
C. 22/7
D. 22/7r
Answer - C
25. A train reaches from K statito to L station in 45 minutes at the speed of 60km/hr. If at the time of coming back his speed is decreased by 6km/hr., then how more time train will take to reach K?
A. 25 min
B. 50 min
C. 15 min
D. 30 min
Answer - B
At time of coming back train speed is 60-6=54km/hr.
Or 15 mitre /second.
Time taken at return (60×5/18×45)÷15=750÷15=50 minutes.
26. A man passes through the diagonal of a square ground in 3 seconds at the speed of 6km/hr. What is the area of the ground?
A. 1.62 sq.mt.
B. 13.6 sq.mt
C. 12.5 sq.mt
D. 15.36 sq.mt
Answer - A
At speed of 6km/hr, the man passes in 3 seconds 3600/6000×3=1.8 mt.
Square of the diagonal x root over 2
So, x root over 2=1.8
or, x=1.8/root over 2
or, x to the power 2=3.24/2
or, x= 1.62 sq.mt.
27. The ratio between the perimeter and the breadth of a rectangle is 5:1. If the area of the rectangle 216 sq.cm, then what is the length of the rectangle?
A. 24cm
B. 18cm
C. 16cm
D. 12cm
Answer - B
Solve - 2(L+B):B=5:1
Or, 2L+2B:B=5:1
Or, 2L+2B/B=5/1
Or, 2L+2B=5B
Or, 2L=5B-2B
Or, 2L=3B
Or, L:B=3:2
Let L is 3x and B is 2x
According to question
3x ×2x=216
Or, x=6
So, length of the rectangle is 3×6=18cm.
28. The difference between the digits of a two digits number is one-twelfth of the number. What is definitely the sum of the digits of that number?
A. 8
B. 10
C. 6
D. Data inadequate
Answer - D
29. 75% of a number, when added to 75 is equal to the number. What is the number?
A. 380
B. 300
C. 226
D. 215
Answer - B
Solve - according to the question
0.75x + 75=x
Or, x - 0.75x=75
Or, 0.25x=75
Or, x =300
30. If 70% of the students in a school are boys and the number of girls be 504, then what is the number of boys?
A. 3158
B. 2167
C. 1176
D. 1080
Answer - C
Solve - Total students in the school
30%=504
Or, 100%=504/30×100
Or, 100%=1680
So, boys are 1680 - 504=1176
31. What is the smallest number by which 3600 be divided to make it perfect cube?
A. 300
B. 180
C. 450
D. 560
Answer - C
32. The ratio of a man's and a women's work is 5:3. If 3 men and 5 women take 17 days to do a piece of work, how many days will 5 men and 3 women take?
Answer - B
Solve - ratio of work power of a man and woman is 5:3
So, work power of 3 men = work power of 5 women.
5 men = 5×5/3 women
25/3 women + 3 women =34/3 women.
So, 10 women work in 17 days
Or, 1 woman work in 17×10
Or, 34/3 women work in 170×3/34=15 days.
33. If A gets 25% more than B and B gets 20% more than C. The share of C out of the sum of Rupees 740 is?
A. Rs. 300
B. Rs. 200
C. Rs. 240
D. Rs. 350
Answer - B
Let C gets 100 Rs. So B gets 120 Rs. A gets 25% more than B, so A gets 120 - 120 of 25%=120+30=150 Rs. Together they get 100+120+150=370 Rs. So, C gets 200 Rs.
34. The side of a square is doubled. How many time will the area increase?
A. 9
B. 4
C. 2
D. 3
Answer- D
Solve - side of a square 10 units. So area is 10×10=100 sq.unit. If side is doubled 10×2=20 units. Area will be 20×20=400 sq.unit.
400-100=300 sq.unit.
Area increase 3 times.
35. Which of the following fraction is the largest?
4/5, 7/9, 11/13, 17/19
A. 17/19
B. 11/13
C. 7/9
D. 4/5
Answer - A
36. The population of city increases at the rate of 4% p.a. But there is an additional annual increase of 1% in the population due to influx of job seeders. The percentage increase in the population after 2 years is__.
A. 10
B. 10.25
C. 10.75
D. 11
Answer - B
Solve - first year population increase 4%+1%=5%
Second year increased (100+5)×5%=5.25%
After 2 it will be (5+5.25)%=10.25%
37. After spending 1/2 of his salary for household expenses, 1/4th for rent and 1/5th for travel expenses, man deposits the rest in the bank. If his monthly deposits in the bank account to Rs. 50. What is his monthly salary?
A. 800
B. 900
C. 500
D. 1000
Answer - D
Let his salary is 100Rs. Household expenses 1/2 of his salary or 100×1/2=50Rs.
For rent he expenses 1/4 or 100×1/4=25Rs. Travel expenses 100×1/5=20Rs.
Total expenses 50+25+20=95Rs.
Deposits in the bank is 100-95=5Rs.
According to the question
5Rs=50Rs
Or, 1Rs. =50/5 Rs.
Or, 100Rs.=50/5×100=1000Rs.
38. By how much percent must 68 be increased to change it to 85?
A. 20%
B. 100/3%
C. 25%
D. 50/3%
Answer - C
85-68=17
17×100/69=25%
39. Six students obtained 57, 53, 51, 41 and 23 marks in an examination. The teacher however, gave the last three students additional marks just enough to ensure that they had the minimum of 50 marks. In the process, the average score of the students improve by (approx).
A. 6
B. 5
C. 4
D. 4.5
Answer - B
Solve - First 3 students get number above 50. Last 3 students get number below of 50. For 50 number teacher gives 50-47=3 , 50-41=9 and 50-33=17. Total number give 3+9+17=29. So, average number given by the teacher 29/6=5(about).
40. If A, B and C earn Rs. 150 per day while A and C earn Rs. 94 per day and B and C earn Rs. 76 per day. Then C's earnings per day is----
A. Rs. 40
B. Rs. 20
C. Rs. 90
D. Rs. 36
Answer - B
Solve - B earns per day 150-94=56 Rs.
C earns per day 76-56=20 Rs.
40. A cube of lead with edges measuring 6 cm. each is melted and formed in 27 equal cubes. What will be the length of the edges of the new cubes?
A. 1.5cm
B. 0.5cm
C. 2cm
D. 1cm
Answer - C
Solve - volume of the cube is 6×6×6=216 cubic cm.
Let new each side of small cubes are X.
So, 27X^3=216
Or, X=2
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